Find the compound interest correct to the nearest rupee on rupee 2400 for 2.5 years at 5 percent per annum
Principal(P) = Rs 2400
Rate of Interest(r ) = 5%
Time = 2.5 years
Here first we take n = 2 years.
A = P( 1 + r /100)n Where A = Amount and n = number of years
A = 2400 (105/100)2
A = 2400 ( 105 / 100 )^2
A = Rs 2646
The Amount after two years = Rs 2646
Now Principal = Rs 2646
Simple interest for last ½ year is = PRT/100 = (2646 × 5 × 1 / 2) / 100 = Rs.66.15
Amount after 2 ½ year = Rs 2646 + Rs 66.15 = Rs 2712.15
C.I = A - P
C.I = Rs 2712.15 - Rs 2400 = Rs312.15
∴ The compound interest is Rs 312.15.
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