Find the compound interest on Rs.1000 at the rate of 8% per annum for 112 years when interest is compounded half-yearly.
Given: Principal (P) = Rs.1000
Time (t) = 112 years
⇒112×2=3 [As interest is compounded half-yearly.]
Rate (R) = 8% per annum
⇒8%2=4% [As interest is compounded half-yearly.]
Now, we know that,
A=P(1+R100)t
⇒A=1000(1+4100)3
⇒A=1000(104100)3
⇒A=1000×104100×104100×104100
⇒A=Rs.1124.8
∴ CI = A−P =1124.8−1000=Rs.124.8
Hence, compound interest earned = Rs.124.8