Find the compound interest to the nearest rupee on Rs- 10-800 for 2 -1-2 years at 10- per annum-

311

You visited us 311 times! Enjoying our articles? Unlock Full Access!

Byju's Answer

Standard IX

Mathematics

Finding CI When Rate Compounded Annually

Find the comp...

Question

Find the compound interest to the nearest rupee on Rs. 10,800 for $2 - \frac{1}{2}$ years at 10% per annum.

Open in App

Solution

Answer: Amount =18000(1+10100)2

=18000×1110×1110=21780

Interest after 2 years =21780−18000= Rs 3780

Interest after half year =21780×10100×12= Rs 1089

Total interest after 2.5 years =3780+1089= Rs 4869

Suggest Corrections

Similar questions

Q. Find the compound interest, correct to the nearest rupee, on Rs.

2, 400

for

2 \frac{1}{2}

years at

5

per cent per annum.

Q. Find the compound interest to the nearest rupee on Rs.

7500

for

2

years

4

months at

12 %

per annum reckoned annually.

Q. Calculate the compound interest (to the nearest integer, in

R s

.) on

R s 10, 800

for

3

years at

12 \frac{1}{2} %

per annum compounded annually.

Q. Find the compound interest on Rs. 10,800 for 3 years at

12 \frac{1}{2} %

per annum, compounded annually.

Calculate the amount and compound interest on
(a) $R s . 10, 800$ for $3$ years at $12 \frac{1}{2} %$ per annum compounded annually.
(b) $R s . 18, 000$ for $2 \frac{1}{2}$ years at $10 %$ per annum compounded annually.

Join BYJU'S Learning Program

Find the compound interest to the nearest rupee on Rs. 10,800 for 2−12 years at 10% per annum.

Answer: Amount =18000(1+10100)2 =18000×1110×1110=21780 Interest after 2 years =21780−18000= Rs 3780 Interest after half year =21780×10100×12= Rs 1089 Total interest after 2.5 years =3780+1089= Rs 4869

Find the compound interest to the nearest rupee on Rs. 10,800 for $2 - \frac{1}{2}$ years at 10% per annum.

Answer: Amount =18000(1+10100)2

=18000×1110×1110=21780

Interest after 2 years =21780−18000= Rs 3780

Interest after half year =21780×10100×12= Rs 1089

Total interest after 2.5 years =3780+1089= Rs 4869