Find the compound interest when principal is Rs. $2000$ and the rate is $10 %$ per annum compounded annually for $2$ years.

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Solution

$P = 2000, R a t e = 10 %$
$a n d T = 2 y e a r s$
Then
$C o m p o u n d I n t e r e s t = p (1 + \frac{R}{100})$
$= 2000 {(1 + \frac{10}{100})}^{2}$
$= 2000 {(\frac{11}{10})}^{2}$
$= 2000 \times \frac{121}{100}$
$= 2420$
Compound Interest $2420$ Rupees

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Find the compound interest when principal is Rs. 2000 and the rate is 10% per annum compounded annually for 2 years.

P=2000,Rate=10%andT=2yearsThenCompoundInterest=p(1+R100) =2000(1+10100)2 =2000(1110)2 =2000×121100 =2420Compound Interest 2420 Rupees

Find the compound interest when principal is Rs. $2000$ and the rate is $10 %$ per annum compounded annually for $2$ years.

$P = 2000, R a t e = 10 %$
$a n d T = 2 y e a r s$
Then
$C o m p o u n d I n t e r e s t = p (1 + \frac{R}{100})$
$= 2000 {(1 + \frac{10}{100})}^{2}$
$= 2000 {(\frac{11}{10})}^{2}$
$= 2000 \times \frac{121}{100}$
$= 2420$
Compound Interest $2420$ Rupees