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Question

Find the compound intersect on Rs,25000 at the rate of interest 12% per annum for three years.

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Solution

Given that,
p=Rs.25000, r=12%, t=3 years
C.I.=p(1+r100)t
C.I.=25000(1+12100)3
C.I.=25000×(1.12)3
C.I.=Rs.35123.2

Hence, the compound interest is Rs.35123.2

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