Find the compounded ratio of $2 : 3$ and $5 : 7$

14 : 15

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6 : 35

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41 : 32

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10 : 21

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Solution

The correct option is C $10 : 21$
By the defination of compound ratio $2 : 3$ and $5 : 7$ can be expressed as
$\frac{2}{3} \times \frac{5}{7} = \frac{10}{21}$
Hence $10 : 21$

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Similar questions

5 : 7, 14 : 10

2 : 3

4 \frac{1}{10} - [2 \frac{1}{2} - {\frac{5}{6} - (\frac{2}{5} + \frac{3}{10} - \frac{4}{15})}]

Class	1-5	6-10	11-15	16-20	21-25	26-30	31-35	35-40	41-45
Frequency	7	10	16	32	24	16	11	5	2

Marks	$0 - 4$	$5 - 9$	$10 - 14$	$15 - 19$	$20 - 24$	$25 - 29$	$30 - 34$	$35 - 39$
Frquency	$2$	$5$	$7$	$13$	$21$	$16$	$8$	$3$

\frac{2^{\frac{1}{2}} \times 3^{\frac{1}{3}} \times 4^{\frac{1}{4}}}{10^{- \frac{1}{5}} \times 5^{\frac{3}{5}}} \div \frac{3^{\frac{4}{3}} \times 5^{- \frac{7}{5}}}{4^{- \frac{3}{5}} \times 6}

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