The correct option is A a2>8b2
Equation of tangent of
y2=4ax in slope form at (x1,y1) is
y1=mx1+am ....(1)
Equation of normal at (2bt1,bt21) on x2=4by
x+t1y=2bt1+bt31
It passes through (x1,y1)
∴x1+t1y1=2bt1+bt31 ....(2)
(1) & (2) are same equation so compare
1t1=−m1=am(2bt1=bt31)
t1m=−1
−m2t1(2b+bt21)=a
⇒m(2b+bt21)=a ....(3)
Put m=1t1 in equation (3)
2b+bt21=−at1
bt21+at1+2b=0
t1 will be real if D>0
a2>8b2