Question

Find the consecutive perfect squares between which the following numbers lie: 123456

Answer 1

R.E.F image

Q. Find the least number to be added to get

a perfect square $123456$

$so{l}^n$ First we find $\sqrt{123756}$ by division method

$9<12<16$

$3^2<12<4^2$

$62\times 2=124$

$63\times 3=189$

$65\times 5=325$

$66\times 6=396$

$702\times 2=1404$

hence $(351{)}^2<123456<(352{)}^2$

Hence two consecutive perfect square are $351$ and $352$