Question

Find the consecutive perfect squares between which the following numbers lie: 4567

Answer 1

R.E.F image

First we find the square root of

$4567$ by division method.

$126\times 6=756$

$127\times 7=889$

$128\times 8=1024>967$

Since we get the remiander $78$

hence $4567$ is not a perfect square,

So the consecutive perfect square between

the number $4567$ lie is

$(67{)}^2<4567<(68{)}^2$

$67$ and $68$