Find the continued product :
$(x + 1) (x - 1) (x^{2} + 1)$

Open in App

Solution

$(x + 1) (x - 1) (x^{2} + 1)$
as $(a + b) (a - b) = a^{2} - b^{2}$
$= (x^{2} - 1) (x^{2} + 1)$
$= x^{4} - 1$

Suggest Corrections

Similar questions

Find the continued products:
(i) $(x + 1) (x - 1) (x^{2} + 1)$
(ii) $(x - 3) (x + 3) (x^{2} + 9)$
(iii) $(3 x - 2 y) (3 x + 2 y) (9 x^{2} + 4 y^{2})$
(iv) $(2 p + 3) (2 p - 3) (4 p^{2} + 9)$

Q. If

x = 3 - 2 \sqrt{2}

, find the value of:
i)

\frac{1}{x}

ii)

x + \frac{1}{x}

iii)

x - \frac{1}{x}

iv)

\sqrt{x} + \frac{1}{\sqrt{x}}

\sqrt{x} - \frac{1}{\sqrt{x}}

vi)

x^{2} + \frac{1}{x^{2}}

vii)

x^{2} - \frac{1}{x^{2}}

Q. If

x - \frac{1}{x} = - 1

, find the value of

x^{2} + \frac{1}{x^{2}}

(x - 1) (x + 1) (x^{2} + 1) (x^{4} + 1)

Q. If

x^{2} + \frac{1}{x^{2}} = 18,

find the values of

x + \frac{1}{x} and x - \frac{1}{x} .

Join BYJU'S Learning Program

Find the continued product :(x+1)(x−1)(x2+1)

(x+1)(x−1)(x2+1)as (a+b)(a−b)=a2−b2=(x2−1)(x2+1)=x4−1

Find the continued product :
$(x + 1) (x - 1) (x^{2} + 1)$

$(x + 1) (x - 1) (x^{2} + 1)$
as $(a + b) (a - b) = a^{2} - b^{2}$
$= (x^{2} - 1) (x^{2} + 1)$
$= x^{4} - 1$