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Question

Find the continued products :
(i)(x+2)(x2)(x24)
(ii)(2x1)(2x+1)(4x2+1)
(iii)(ax+b)(axb)(a2x2+b2)
(iv)(x+1x)(x1x)(x2+1x2)

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Solution

1)(x+2)(x2)(x24)
=(x24)(x24)
=x4+168x2

2)(2x1)(2x+1)(4x2+1)
=(4x21)(4x2+1)
=16x41

3)(ax+b)(axb)(a2x2+b2)
=(a2x2b2)(a2x2+b2)
=a4x4b4

4)(x+1x)(x1x)(x2+1x2)

=(x21x2)(x2+1x2)

=x41x4

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