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Question

Find the coordinates of points which trisect the line segment joining (1, –2) and (–3, 4). [4 MARKS]

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Solution

Formula: 1 Mark
Application: 1 Mark
Coordinates of point of trisection: 2 Marks


Let A(1, -2) and B(-3, 4) be the given points.

Let the points of trisection be P and Q. Then,

AP=PQ=QB=λ (say).

PB=PQ+QB=2λ and AQ=AP+PQ=2λ

AP:PB=λ:2λ=1:2 and

AQ:QB=2λ:λ=2:1

So, P divides AB internally in the ratio 1:2 while Q divides internally in the ratio 2:1.

Thus, the coordinates of P are

P(1×(3)+2×11+2,1×4+2×(2)1+2)=P(13,0)

The coordinates of Q are

Q(2×(3)+1×12+1,2×4+1×(2)2+1)=Q(53,2)

Hence, the two points of trisection are (13,0) and (53,2) respectively


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