Find the coordinates of the centroid of a ΔABC whose vertices are
A(5,10), B (10,0), C(5,4)
(203,8)
Vertices of a △ABC are A(x1,y1),B(x2,y2) and C(x3,y3)
its centroid =(x1+x2+x33,y1+y2+y33)
A(5,10)⇒x1=5, y1=10
B(10,10)⇒x2=10, y2=10
C(5,4)⇒x3=5, y3=4
Centroid =(5+5+103,243)
centroid =(203,8)