Find the coordinates of the foot of the perpendicular drawn from the origin to the plane 5y+8=0
A
(0,−185,2)
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B
(0,85,0)
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C
(825,0,0)
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D
(0,−85,0)
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Solution
The correct option is D(0,−85,0) 5y+8=0 ⇒y=−85 This represents a plane parallel to xz-plane which cuts negative y-axis at a distance of 85 units from the origin. ∴ Required coordinate is (0,−85,0)