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Question

Find the coordinates of the midpoint of the line joining the points (3,10) and (6,8).

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Solution

We know that the mid point formula M=(x,y) of the two points (x1,y1) and (x2,y2) is:

(x,y)=(x1+x22,y1+y22)

Here, the given points are (3,10) and (6,8), therefore,

(x,y)=(x1+x22,y1+y22)(x,y)=(3+62,10+(8)2)(x,y)=(32,1082)(x,y)=(32,22)(x,y)=(32,1)

Hence, the coordinates of the mid point are (32,1).

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