Question

Find the coordinates of the midpoint P of seg AB if A $\equiv$(3.5, 9.5), B$\equiv$ (-1.5, 0.5)

Answer 1

$$\begin{gathered} \mathrm{P}\mathrm{is}\mathrm{the}\mathrm{mid}\mathrm{point}\mathrm{of}\mathrm{seg}\mathrm{AB}. \\ \mathrm{Given}:\mathrm{A}\equiv \left(3.5,9.5\right)\mathrm{and}\mathrm{B}\equiv \left(-1.5,0.5\right) \\ \mathrm{Here},x_1=3.5,y_1=9.5,x_2=-1.5\mathrm{and}{y}_2=0.5. \\ \mathrm{Let}\mathrm{P}\equiv \left(x,y\right) \\ \mathrm{By}\mathrm{mid}\mathrm{point}\mathrm{formula}, \end{gathered}$$

$$\begin{gathered} x=\frac{x_1+x_2}{2} \\ \Rightarrow x=\frac{3.5-1.5}{2} \\ \therefore x=1 \end{gathered}$$

$$\begin{gathered} y=\frac{y_1+y_2}{2} \\ \Rightarrow y=\frac{9.5+0.5}{2} \\ \therefore y=5 \end{gathered}$$

$\therefore \text{C}\mathrm{oordinate}\text{s}\mathrm{of}\mathrm{point}\mathrm{P}\equiv \left(1,5\right)$