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Question

Find the coordinates of the point where the line through (5, 1, 6) and (3, 4, 1) crosses the
(i) yz-plane
(ii) zx-plane

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Solution

i The equation of the line through the points (5, 1, 6) and (3, 4, 1) isx-53-5 = y-14-1 = z-61-6x-5 -2 = y-13 = z-6-5The coordinates of any point on this line are of the formx-5-2 = y-13 = z-6-5 = λx = -2λ+5; y = 3λ+1; z = -5λ+6So, the coordinates of the point on the given line are -2λ+5, 3λ+1, -5λ+6. Since this point lies on the YZ- plane, x = 0-2λ + 5 = 0λ = 52So, the coordinates of the point are-2λ+5, 3λ+1, -5λ+6=-2 52+5, 3 52+1, -5 52+6=0, 172, 132

ii The equation of the line through the points (5, 1, 6) and (3, 4, 1) isx-53-5=y-14-1=z-61-6x-5-2=y-13=z-6-5The coordinates of any point on this line are of the formx-5-2=y-13=z-6-5=λx=-2λ+5; y=3λ+1; z=-5λ+6So, the coordinates of the point on the given line are -2λ+5, 3λ+1, -5λ+6. Since this point lies on the ZX - plane, y=03λ+1=0λ=-13So, the coordinates of the point are-2λ+5, 3λ+1, -5λ+6=-2 -13+5, 3 -13+1, -5 -13+6=173, 0, 233

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