Find the coordinates of the point which divides the line segment joining the points (6, 3) and (–4, 5) in the ratio 3:2 internally.

(0, 12/5)

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(0, 27/5)

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(0, 1/5)

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(0, 21/5)

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Solution

The correct option is D
(0, 21/5)

Let P(x, y) be the required point. Then,

$x$ = $\frac{3 \times (- 4) + 2 \times 6}{3 + 2}$ and $y$ = $\frac{3 \times 5 + 2 \times 3}{3 + 2}$

$\Rightarrow x$ = 0 and $y$ = $\frac{21}{5}$

So the coordinates of P are (0, $\frac{21}{5}$ )

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Similar questions

Q. Find the abscissa of the point which divides the line segment joining the points

(6, 3)

and

(- 4, 5)

in the ratio

3 : 2

internally.

Q. The point which divides the line segment joining the points

(6, 3)

and

(- 4, 5)

in the ratio

3 : 2

externally is

Q. Find coordinates of point which divides the line segment internally, joining the points

(5, 7)

and

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in ratio

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Find the coordinates of the point which divides the line segment joining the points $(- 2, 3, 5)$ and $(1, - 4, 6)$ in the ratio. (i) 2 : 3 internally (ii) 2 : 3 externally.

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Find the coordinates of the point which divides the line segment joining the points (6, 3) and (–4, 5) in the ratio 3:2 internally.

The correct option is D (0, 21/5) Let P(x, y) be the required point. Then, x = 3×(−4)+2×63+2 and y = 3×5+2×33+2 ⇒x = 0 and y = 215 So the coordinates of P are (0, 215)

The correct option is D
(0, 21/5)

Let P(x, y) be the required point. Then,

$x$ = $\frac{3 \times (- 4) + 2 \times 6}{3 + 2}$ and $y$ = $\frac{3 \times 5 + 2 \times 3}{3 + 2}$

$\Rightarrow x$ = 0 and $y$ = $\frac{21}{5}$

So the coordinates of P are (0, $\frac{21}{5}$ )