Question

Find the coordinates of the points of intersection of the straight lines whose equations are
$2x-3y+5=0$ and $7x+4y=3$.

Answer 1

Given $2x-3y+5=0$.....(1) & $7x+4y=3$.........(2)

Multiply $\left(1\right)$ with $4$ and $\left(2\right)$ with $3$

we get,

$\left(1\right)\times 4\Rightarrow 8x-12y+20=0$ ...... (3)

$\left(2\right)\times 3\Rightarrow 21x+12y-9=0$ ....... (4)

Adding (3) and (4), we get

$x=\frac{-11}{29}$ and substitute this $x$ in any equation and we get $y=\frac{41}{29}$