Find the coordinates of the points where the circle $x^{2} + y^{2} + 4 x - 4 y - 5 = 0$ intersects the x-axis.

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Solution

On the x-axis, $y = 0$ .
Putting $y = 0$ in the equation of circle, we get,
$x^{2} + 4 x - 5 = 0$
$(x - 1) (x + 5) = 0$
$x = 1$ or $x = - 5$
Therefore, coordinates on x-axis : $(1, 0)$ and $(- 5, 0)$ .

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Find the coordinates of the points where the circle x2+y2+4x−4y−5=0 intersects the x-axis.

On the x-axis, y=0.Putting y=0 in the equation of circle, we get,x2+4x−5=0(x−1)(x+5)=0x=1 or x=−5Therefore, coordinates on x-axis : (1,0) and (−5,0).

Find the coordinates of the points where the circle $x^{2} + y^{2} + 4 x - 4 y - 5 = 0$ intersects the x-axis.

On the x-axis, $y = 0$ .
Putting $y = 0$ in the equation of circle, we get,
$x^{2} + 4 x - 5 = 0$
$(x - 1) (x + 5) = 0$
$x = 1$ or $x = - 5$
Therefore, coordinates on x-axis : $(1, 0)$ and $(- 5, 0)$ .