Find the coordinates of the points where the circle $x^{2} + y^{2} + 4 x - 4 y - 5 = 0$ intersects the y-axis.

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Solution

On the y-axis, $x = 0$ .
Putting $x = 0$ in the equation of circle, we get,
$y^{2} - 4 y - 5 = 0$
$(y + 1) (y - 5) = 0$
$y = - 1$ or $y = 5$
Coordinates on the y-axis :
$(0, - 1)$ and $(0, 5)$

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Find the coordinates of the points where the circle x2+y2+4x−4y−5=0 intersects the y-axis.

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Find the coordinates of the points where the circle $x^{2} + y^{2} + 4 x - 4 y - 5 = 0$ intersects the y-axis.

On the y-axis, $x = 0$ .
Putting $x = 0$ in the equation of circle, we get,
$y^{2} - 4 y - 5 = 0$
$(y + 1) (y - 5) = 0$
$y = - 1$ or $y = 5$
Coordinates on the y-axis :
$(0, - 1)$ and $(0, 5)$