Find the coordinates of the points where the graph of line $3 x + 2 y = 6$ drawn meets the co-ordinate axes?

x-axis at

(a, 0) = (- 2, 0)

; y-axis at

(0, b) = (0, - 3)

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x-axis at

(a, 0) = (2, 0)

; y-axis at

(0, b) = (0, 3)

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x-axis at

(a, 0) = (- 2, 0)

; y-axis at

(0, b) = (0, 3)

No worries! We‘ve got your back. Try BYJU‘S free classes today!

x-axis at

(a, 0) = (2, 0)

; y-axis at

(0, b) = (0, - 3)

No worries! We‘ve got your back. Try BYJU‘S free classes today!

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Solution

The correct option is B x-axis at $(a, 0) = (2, 0)$ ; y-axis at $(0, b) = (0, 3)$
$T h e g i v e n e q u a t i o n i s 3 x + 2 y = 6 ⟹ y = \frac{6 - 3 x}{2} H e r e x i s t h e i n d e p e n d e n t v a r i a b l e . W e a s s i g n a t l e a s t a n y 3 v a l u e s o f x a n d o b t a i n t h e c o r r e s p o n d i n g v a l u e s o f y . x = - 2 ⟶ y = 6, x = 4 ⟶ y = - 3, x = 8 ⟶ y = - 9. S o t h e o r d e r e d p a i r e s o f v a l u e s o f (x, y) = (- 10, - 6), (10, 2) & (20, 6) . N o w w e p l o t t h e m o n a g r a p h . F r o m t h e g r a p h w e o b t a i n t h e x - i n t e r c e p t a = 2 & y - i n t e r c e p t b = 3 ∴ T h e p o i n t s o f i n t e r s e c t i o n o f t h e g i v e n l i n e w i t h X - a x i s i s (a, 0) = (2, 0) & T h e p o i n t s o f i n t e r s e c t i o n o f t h e g i v e n l i n e w i t h Y - a x i s i s (0, b) = (0, 3) A n s - O p t i o n B .$

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Find the coordinates of the points where the graph of line 3x+2y=6 drawn meets the co-ordinate axes?

Find the coordinates of the points where the graph of line $3 x + 2 y = 6$ drawn meets the co-ordinate axes?