Given coordinates of P as (4,2,−6) and Q as (10,−16,6)
Let R and S be the points of trisection of line segment PQ.Then R divides PQ in the ratio 1:2 and S is the mid-point of RQ.
Let the coordinates of R be (x,y,z)
By using section formula,
x=1(10)+2(4)1+2,y=1(−16)+2(2)1+2,z=1(6)+2(−6)1+2
⇒x=183,y=−123,z=−63
⇒x=6,y=−4,z=−2
So, the coordinates of R are (6,−4,−2).
Now, since S is the mid-point of RQ.