Question

Find the correct answer for the questions given in Column I, selecting them from Column II

Answer 1

A. Distance from starting point $=\sqrt{6^2+8^2}=\sqrt{100}=10$

B. From figure, $\angle ABC={40}^{\circ },\angle ADC={90}^{\circ }$ and $\angle BAC={90}^{\circ }$

$\angle BAD={90}^{\circ }-\angle ABD={90}^{\circ }-{40}^{\circ }={50}^{\circ }$

Now, $\angle CAD={90}^{\circ }-\angle BAD={90}^{\circ }-{50}^{\circ }={40}^{\circ }$

C. $r=\frac{d}{2}=\frac{8cm}{2}=4cm,h=3cm$

$l=\sqrt{r^2+h^2}=\sqrt{4^2+3^2}=5cm$

D. $\tan \theta .\cot \theta =\sec \theta .x$

$\Rightarrow 1=\sec \theta .x$

So, $x=\cos \theta$

E. $\cos ({90}^{\circ }-\theta )=\sin \theta$

$A.-\left(6\right),B.-\left(4\right),C.-\left(1\right),D.-\left(3\right),E.-\left(5\right)$