Find the correct option when x is the subject of the formula of given expression.

$a (x - b) = a^{2} + b x$

a(a + b)/(a - b)

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a(a - b)/(a + b)

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b (a + b)/(a - b)

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ab(a + b)/(a - b)

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Solution

The correct option is A
a(a + b)/(a - b)

$a (x - b) = a^{2} + b x$

$x (a - b) = a^{2} + a b$

$x = \frac{a (a + b)}{(a - b)}$

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Similar questions

$a^{2} + b c + a b + a c = ? (a) (a + b) (a + c) (b) (a + b) (b + c) (c) (b + c) (c + a) (d) a (a + b + c)$

Q. Prove that

∣ ∣ ∣ ∣ \begin{matrix} b + c & c + a & a + b c + a & a + b & b + c a + b & b + c & c + a \end{matrix} ∣ ∣ ∣ ∣ == 2 (a + b + c) (a b + b c + c a - a^{2} - b^{2} - c^{2})

Q. The determinant

|\begin{matrix} b^{2} - a b & b - c & b c - a c \\ a b - a^{2} & a - b & b^{2} - a b \\ b c - c a & c - a & a b - a^{2} \end{matrix}|

equals

(a)

a b c (b - c) (c - a) (a - b)

(b)

(b - c) (c - a) (a - b)

(c)

(a + b + c) (b - c) (c - a) (a - b)

(d) none of these

Q. Tick (✓) the correct answer:
a² + bc + ab + ac = ?
(a) (a + b)(a + c)
(b) (a + b)(b + c)
(c) (b + c)(c + a)
(d) a(a + b + c)

The determinant
$∣ ∣ ∣ ∣ ∣ \begin{matrix} b^{2} - a b & b - c & b c - a c a b - a^{2} & a - b & b^{2} - a b b c - a c & c - a & a b - a^{2} \end{matrix} ∣ ∣ ∣ ∣ ∣$ equals to:

(a) abc(b-c)(c-a)(a-b)
(b) (b-c)(c-a)(a-b)
(c) (a+b+c)(b-c)(c-a)(a-b)
(d) None of these

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Find the correct option when x is the subject of the formula of given expression. a(x–b)=a2+bx

The correct option is A a(a + b)/(a - b) a(x–b)=a2+bx x(a−b)=a2+ab x=a(a+b)(a−b)

Find the correct option when x is the subject of the formula of given expression.

$a (x - b) = a^{2} + b x$

The correct option is A
a(a + b)/(a - b)

$a (x - b) = a^{2} + b x$

$x (a - b) = a^{2} + a b$

$x = \frac{a (a + b)}{(a - b)}$