Find the correct relation from the following:

Work done=charge

\times

power

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Work done=charge

\times

potential difference

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Work done=current

\times

voltage

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All

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Solution

The correct option is A Work done=charge $\times$ potential difference
We know that the work done in the electric field is the change in electrical potential energy.
Thus, the electrical potential energy $U = q V = c h a r g e \times p o t e n t i a l$ $d i f f e r e n c e$

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Similar questions

Q. (a) State the relation between potential difference, work done and charge moved.
(b) Calculate the work done in moving a charge of 4 coulombs from a point at 220 volts to another point at 230 volts.

Question 9
Which of the following represents voltage?

(a) $\frac{W o r k d o n e}{C u r r e n t \times T i m e}$
(b) $W o r k d o n e \times C h a r g e$
(c) $W o r k d o n e \times \frac{T i m e}{C u r r e n t}$
(d) $W o r k d o n e \times C h a r g e \times T i m e$

Q. If voltage is work done per charge and electric potential is the wrk done to move a charge from a reference point to infinity point . Are they same ?

Work done in moving an electric charge and difference in potential is called potential difference here what is the work done

Q. Question 9
Which of the following represents voltage?

(a)

\frac{W o r k d o n e}{C u r r e n t \times T i m e}

(b)

W o r k d o n e \times C h a r g e

(c)

W o r k d o n e \times \frac{T i m e}{C u r r e n t}

(d)

W o r k d o n e \times C h a r g e \times T i m e

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Find the correct relation from the following:

The correct option is A Work done=charge × potential differenceWe know that the work done in the electric field is the change in electrical potential energy.Thus, the electrical potential energy U=qV=charge×potential difference

The correct option is A Work done=charge $\times$ potential difference
We know that the work done in the electric field is the change in electrical potential energy.
Thus, the electrical potential energy $U = q V = c h a r g e \times p o t e n t i a l$ $d i f f e r e n c e$