Find the cost of heating 4.6kg of water from 25∘C to the boiling point, assuming that no energy is wasted. Electrical energy costs 25Paisa per kWh.
[Take specific heat capacity of water, s=1cal g−1∘C−1]
A
5Paisa
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B
10Paisa
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C
15Paisa
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D
50Paisa
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Solution
The correct option is B10Paisa Given: m=4.6kg;s=1cal g−1∘C−1 ΔT=(100−25)=75∘C
The amount of heat required is,
H=msΔT
H=(4.6×103×1×75)cal
Total electrical energy consumed is,
We=(4.2×4.6×103×1×75)J
Power=Wt
P=(4.2)(4.6×103)(75)60×60×103kWh=0.4kWh
Total cost is,
C=0.4×25=10paisa
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Hence, (B) is the correct answer.