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Question

# Find the cost of heating 4.6 kg of water from 25∘C to the boiling point, assuming that no energy is wasted. Electrical energy costs 25 Paisa per kWh. [Take specific heat capacity of water, s=1 cal g−1∘C−1]

A
5 Paisa
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B
10 Paisa
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C
15 Paisa
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D
50 Paisa
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Solution

## The correct option is B 10 PaisaGiven: m=4.6 kg; s=1 cal g−1∘C−1 ΔT=(100−25)=75∘C The amount of heat required is, H=msΔT H=(4.6×103×1×75) cal Total electrical energy consumed is, We=(4.2×4.6×103×1×75) J Power=Wt P=(4.2)(4.6×103)(75)60×60×103 kWh=0.4 kWh Total cost is, C=0.4×25=10 paisa <!--td {border: 1px solid #ccc;}br {mso-data-placement:same-cell;}--> Hence, (B) is the correct answer.

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