Find the cost of painting $20$ cylindrical pillars of an institution at the rate of Rs. $3$ per $m^{2}$ , if the radius and the height of each pillar are $36 c m$ and $3.5 m$ respectively.

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Solution

Length or height of pillar $= 3.5 m$
Radius of each pillar $= 36 c m = 0.36 m$
Curved Surface Area of pillar $= 2 π r h = 2 π \times 0.36 \times 3.5 m^{2} = 7.91 m^{2}$
Total area to be painted $= 7.91 \times 20 m^{2}$
$= 158.20 m^{2}$
Cost of painting $= R s . 158.20 \times 3 = R s . 474.60$ .

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Find the cost of painting 20 cylindrical pillars of an institution at the rate of Rs. 3 per m2, if the radius and the height of each pillar are 36 cm and 3.5 m respectively.

Length or height of pillar =3.5 mRadius of each pillar =36 cm=0.36 mCurved Surface Area of pillar =2πrh=2π×0.36×3.5 m2=7.91 m2Total area to be painted =7.91×20 m2 =158.20 m2Cost of painting =Rs. 158.20×3=Rs. 474.60.

Find the cost of painting $20$ cylindrical pillars of an institution at the rate of Rs. $3$ per $m^{2}$ , if the radius and the height of each pillar are $36 c m$ and $3.5 m$ respectively.

Length or height of pillar $= 3.5 m$
Radius of each pillar $= 36 c m = 0.36 m$
Curved Surface Area of pillar $= 2 π r h = 2 π \times 0.36 \times 3.5 m^{2} = 7.91 m^{2}$
Total area to be painted $= 7.91 \times 20 m^{2}$
$= 158.20 m^{2}$
Cost of painting $= R s . 158.20 \times 3 = R s . 474.60$ .