Find the cost of plastering the inner surface of a well at Rs 9.50 per m², if it is 21 m deep and diameter of its top is 6 m.

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Solution

$Given : Height, h = 21 m Diameter, d = 6 m Radius, r = 3 m Area of the inner surface of the well, S = 2 π r h = 2 π \times 3 \times 21 m^{2} = 2 \times \frac{22}{7} \times 3 \times 21 m^{2} = 396 m^{2} According to question, the cost per m^{2} is Rs 9.50 . ∴ Inner surface cost is Rs 396 \times 9.50 = Rs 3762$

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Find the cost of plastering the inner surface of a well at Rs 9.50 per m2, if it is 21 m deep and diameter of its top is 6 m.

Given:Height, h=21 mDiameter, d= 6 mRadius, r= 3 mArea of the inner surface of the well, S=2πrh=2π×3×21 m2= 2×227×3×21 m2=396 m2According to question, the cost per m2 is Rs 9.50. ∴ Inner surface cost is Rs 396×9.50=Rs 3762

Find the cost of plastering the inner surface of a well at Rs 9.50 per m², if it is 21 m deep and diameter of its top is 6 m.