Question

Question 8

Find the cost of polishing a circular table-top of diameter 1.6 m, if the rate of polishing is $₹15/m^2$
$(Take\pi =3.14)$

Answer 1

Diameter of the circular table top = 1.6 m

$\therefore$ Radius of the circular table top
$=\frac{1.6}{2}=0.8m$

Area of circular table top = $\pi r^2$
$=3.14\times 0.8\times 0.8=2.0096m^2$

Now cost of polishing 1 $m^2$ = ₹ 15
Then cost of polishing 2.0096 $m^2$ = 15 $\times$ 2.0096 = ₹ 30.14 (approx)

Thus, the cost of polishing a circular table top is ₹30.14 (approx)