Question

Find the cost of polishing a circular table-top of diameter $1.6m,$ if the rate of polishing is $Rs.15$ per $m^2$. (Take $\pi =3.14$)

Answer 1

Given: Diameter of the circular table top $=1.6m$

Radius $=\frac{1.6}{2}=0.8m$

Area of the circular table top $=\pi r^2=3.14\times 0.8\times 0.8$

$=2.0096m^2$

Cost for polishing $1m^2$ area $=Rs.15$

Cost for polishing $2.0096m^2$ area $=15\times 2.0096=Rs.30.144$

Therefore, it will cost $Rs.30.144$ for polishing such circular table.