Question

Find the cost of polishing a circular table-top of diameter $1.6m$, if the rate of polishing is $Rs15/m^2$. (Take $\pi =3.14$)

Answer 1

We need to polish only the table top

area to polish = area of circular table

$=\frac{\pi D^2}{4}=\left(3.14\right)\frac{{\left(1.6\right)}^2}{4}{m}^2$

area to polish $=2m^2$

cost of polishing for $1m^2=15Rs.$

Cost of polishing for $2m^2=$?

$=\frac{2\times 15}{1}=Rs.30$

Cost of polishing the table top $=Rs.30$