Find the cost of polishing a circular table top of diameter 1.6 m, if the rate of polishing is $R s .15 / m^{2} .$ . $(T a k e π = 3.14)$

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Solution

Given diameter of table (circular) $= 1.6 m$

radius $= 0.8 m$

area of circle = $π r^{2} = 3.14 \times 0.64 = 2.0096 m^{2}$

Now rate of polishing per meter square $= 15 R s$

Cost of polishing table top = $15 \times 2.0096$

cost = $30.14 m^{2}$

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Find the cost of a polishing a circular table-top of diameter $1.6 m$ , if the rate of polishing is $R s 15 / m^{2}$ . (Take $π = 3.14$ ).

Find the cost of polishing a circular table-top of diameter $1.6 m,$ if the rate of polishing is $R s . 15$ per $m^{2}$ . (Take $π = 3.14$ )

m^{2}

π = 3.14

Question 8

Find the cost of polishing a circular table-top of diameter 1.6 m, if the rate of polishing is $₹ 15 / m^{2}$
$(T a k e π = 3.14)$

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