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Question

Find the cross product of two vectors ¯¯¯¯A=3^i+2^j4^k and B=2^i3^j6^k. Also find the magnitude of A×B

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Solution

Cross product of two vectors,
Hwew
A=3^i+2^j4^ka1=3 a2=2 a3=4
B=2^i3^j6^kb1=2 b2=3 b3=6
is given by:
A×B=∣ ∣ ∣^i^j^ka1a2a3b1b2b3∣ ∣ ∣=^i(a2b3b2a3)^j(a1b3b1a3)+^k(a1b2b1a2)
=∣ ∣ ∣^i^j^k324236∣ ∣ ∣
=^i[(2x6)(3x4)]^j[(3x6)(2x4)]+^k[(3x3)(2x2)]
^i(12+12)^j(18+8)+^k(94)
A×B=24^i+10^j13^k
For magnitude,
|A×B|=a2+b2+c2
=(24)2+(10)2+(13)2
=845
|A×B|=29.06 units


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