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Question

Find the cross products of the vectors
1. a=i2j+3k,b=3i6j+9k
2. a=2i4k,b=i2jk,c=i4j+3k

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Solution

1a=^i2^j+3^kb=3^i6^j+9^ka×b=^i^j^k123369=^i(18+18)^j(99)+^k(6+6)=0
a×b=0
2a=2^i4^kb=^i2^j^kc=^i4^j+3^ka×(b×c)=(a.c)b(a.b)c=((2^i4^k.(^i4^j+3^k)))(^i2^j^k)=((2^i4^k).(^i2^j^k))(^i4^j+3^k)=(2+012)(^i2^j^k)(2+4)(^i4^j+3^k)=14(^i2^j^k)2(^i4j+3^k)=14^i+28^j+14^k2^i+8^j6^k=16^i+36^j+8^k

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