Find the CSA of a cylindrical container of depth 20 m and radius 0.7 m.

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Solution

Given: Height of the cylinder = 20 m
Radius = 0.7 m = $\frac{7}{10} m$

Curved surface area (CSA) of the cylindrical vessel
$= 2 π r h$
$\Rightarrow$ CSA = $2 π \times (\frac{7}{10}) \times 20$
$\Rightarrow$ CSA = $2 \times \frac{22}{7} \times \frac{7}{10} \times 20$
$\Rightarrow$ CSA = $88 m^{2}$
$[1 m a r k]$

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Find the CSA of a cylindrical container of depth 20 m and radius 0.7 m.

Given: Height of the cylinder = 20 m Radius = 0.7 m = 710 m Curved surface area (CSA) of the cylindrical vessel =2πrh ⇒ CSA = 2π×(710)×20 ⇒ CSA = 2×227×710×20 ⇒ CSA = 88 m2 [1 mark]