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Question

Find the cube of (2a6b)


A

8a3216b372a2b+216ab2

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B

8a2216b372a2b+216ab2

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C

8a3216b372a3b+216ab2

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D

8a3216b372a2b+216ab3

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Solution

The correct option is A

8a3216b372a2b+216ab2


We know the identity

(ab)3=a3b33a2b+3ab2

Substituting for the values of a and b

(2a)3(6b)33(2a)2(6b)+3(2a)(6b)2

=8a3216b372a2b+216ab2


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