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Question

Find the cube of:
2a+12a;(a0)

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Solution

2a+12a
Using,(a+b)3=a3+b3+3a2b+3ab2
(2a+12a)3
=(2a)3+(12a)3+3×(2a2)×(12a)+3×(2a)×(12a)2
=8a3+18a3+6a+32a

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