Find the cube of - 2a - 1-2a a - 0

The correct option is A 8a^3 + 6a + 3/2a + 1/8a^3 2a + 12a Using, (a+b)^3=a^3+b^3+3a^2b+3ab^2 (2a + 12a)^3 =(2a)^3+(12a)^3+3× (2a^2)× (1 ...

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Binomial Coefficients

Find the cube...

Question

Find the cube of :
$2 a + \frac{1}{2 a} (a \neq 0)$

8 a^{3} + 6 a + \frac{3}{2 a} + \frac{1}{8 a^{3}}

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8 a^{3} - 6 a + \frac{3}{2 a} + \frac{1}{8 a^{3}}

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a^{3} + 6 a + \frac{3}{2 a} + \frac{1}{8 a^{3}}

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a^{3} - 6 a + \frac{3}{2 a} - \frac{1}{8 a^{3}}

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Solution

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Similar questions

2 a + \frac{1}{2 a}

a \neq

(2 a - \frac{1}{2 a})^{3}

8 a^{3} - 6 a + \frac{3}{2 a} - \frac{1}{8 a^{3}}

(2 a - 1)

8 a^{3} - 12 a^{2} + 6 a - 1

Find the cube of $(2 a - 6 b)$

If $2 a - \frac{3}{a} = 1$ , then, the value of $8 a^{3} - \frac{27}{a^{3}}$ is not equal to 18 .

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