Question

Find the cube of $(2-\frac{1}{3})$

• A. $8-\frac{1}{27}$
• B. $\frac{125}{27}$
• C. $\frac{25}{9}$
• D. $\frac{343}{27}$

Answer 1

Answer: (B)

$\frac{125}{27}$

We need to find cube of $(2-\frac{1}{3})$

Thus ${\left[\right(2-\frac{1}{3}\left)\right]}^3={\left[\frac{5}{3}\right]}^3=\frac{5^3}{3^3}=\frac{125}{27}$