Find the cube of - 2x-1x

(2x+1x)^3= (2x)^3+ #10;(1x)^3+3 × 2x ×1x #10;(2x+1x) =8x^3+1x^3+6 (2x+1x)=8x^3+1x^3+12x+6x =8x^3+12x+6x+1x^3 ...

You visited us 1 times! Enjoying our articles? Unlock Full Access!

Algebraic Identity (a+b)^3

Find the cube...

Question

Find the cube of :
$(2 x + \frac{1}{x})$

Open in App

Solution

Suggest Corrections

Similar questions

Find the cube of :

(i) $a + 2$

(ii) $2 a - 1$

(iii) $2 a + 3 b$

(iv) $3 b - 2 a$

(v) $2 x + \frac{1}{x}$

(vi) $x - \frac{1}{2}$

(v) (2 x + \frac{1}{x})

(2 x + y)

if alpha,beta are the roots of x^2+2x-1=0.find the values of alpha cubed + beta cubed

find the derivative of (5x/cube root of 1-x square)+sin square(2x+3)

Join BYJU'S Learning Program