Find the cube root of 1.728

True

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0.12

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0.102

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0.012

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Solution

The correct option is A
True

Cube root of 1.728 = $\sqrt[3]{\frac{1728}{100}}$

= $\sqrt[3]{\frac{12^{3}}{10^{3}}}$

= $\frac{12}{10}$

= 1.2

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1.728 m^{3}

\sqrt[3]{1.728}

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