Question

find the cube root of :2¹² x 3⁶

Answer 1

$$\begin{gathered} \sqrt[3]{2^{12}\times 3^6} \\ ={\left(2^{12}\times 3^6\right)}^{1/3} \\ ={\left(2^{12}\right)}^{1/3}\times {\left(3^6\right)}^{1/3} \\ =2^{12\times \frac{1}{3}}\times 3^{6\times \frac{1}{3}} \\ =2^4\times 3^2 \\ =16\times 9 \\ =144 \end{gathered}$$