Question

Find the cube root of $74088$.

Answer 1

On prime factorising, we get,

$74088=2\times 2\times 2\times 3\times 3\times 3\times 7\times 7\times 7$

$=2^3\times 3^3\times 7^3$.

Then, cube root of $74088$ is:

$\sqrt[3]{374088}=\sqrt[3]{32^3\times 3^3\times 7^3}=2\times 3\times 7=42$.

Therefore, $42$ is the required cube root.