Find the cube root of $10^{9} .$

10^{2}

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10^{3}

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10^{4}

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10^{5}

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Solution

The correct option is A $10^{3}$
Given; $\sqrt[3]{10^{9}}$
$= {(10^{9})}^{\frac{1}{3}}$

$= (10)^{\frac{9}{3}}$

$= 10^{3}$

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Similar questions

Q. Find the number from each of the following expanded forms:
(i) 7 × 10⁴ + 6 × 10³ + 0 × 10² + 4 × 10¹ + 5 × 10⁰
(ii) 5 × 10⁵ + 4 × 10⁴ + 2 × 10³ + 3 × 10⁰
(iii) 9 × 10⁵ + 5 × 10² + 3 × 10¹
(iv) 3 × 10⁴+ 4 × 10² + 5 × 10⁰

Write the numeral whose expanded form is given below:
(i) $6 \times 10^{4} + 3 \times 10^{3} + 0 \times 10^{2} + 7 \times 10^{1} + 8 \times 10^{0}$
(ii) $9 \times 10^{6} + 7 \times 10^{5} + 0 \times 10^{4} + 3 \times 10^{3} + 4 \times 10^{2} + 6 \times 10^{1} + 2 \times 10^{0}$
(iii) $8 \times 10^{5} + 6 \times 10^{4} + 4 \times 10^{3} + 2 \times 10^{2} + 9 \times 10^{1} + 6 \times 10^{0}$

Question 61

$876543 = 8 \times 10^{5} + 7 \times 10^{4} + 6 \times 10^{3} + 5 \times 10^{2} + 4 \times 10^{1} + 3 \times 10^{0}$

Q. Express the number :

8 \times 10^{5} + 7 \times 10^{4} + 5 \times 10^{3} + 4 \times 10^{2} + 6 \times 10^{1} + 9 \times 10^{0}

Q. Write the number :

4 \times 10^{6} + 8 \times 10^{5} + 6 \times 10^{4} + 4 \times 10^{3} + 4 \times 10^{2} + 6 \times 10 + 9 \times 10^{0}

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Find the cube root of 109.

The correct option is A 103Given; 3√109 =(109)13 =(10)93 =103

Find the cube root of $10^{9} .$

The correct option is A $10^{3}$
Given; $\sqrt[3]{10^{9}}$
$= {(10^{9})}^{\frac{1}{3}}$

$= (10)^{\frac{9}{3}}$

$= 10^{3}$