Find the cube root of each of the following numbers by prime factorisation method.
175616 (2) 91125
(i)175616
The given number is 175616.
After resolving the prime factors by prime factorisation, we get
175616 = 2×2×2×2×2×2×2×2×2×7×7×7
Upon grouping the factors we get,
175616 = (2×2×2)×(2×2×2)×(2×2×2)×(7×7×7)
Taking one factor from each group
1756163 = 2 x 2 x 2 x 7 =56
Hence, the required cube root is 56.
(ii)91125
The given number is 91125.
After resolving the prime factors by prime factorisation, we get
91125 = 3×3×3×3×3×3×3×5×5×5
Upon grouping the factors we get,
91125 = (3×3×3)×(3×3×3)×(5×5×5)
Taking one factor from each group
91125 = 3 x 3 x 5 = 45