Question

Find the cube root of $\frac{-512}{343}$?

• A. $\frac{8}{7}$
• B. $\frac{-7}{8}$
• C. $\frac{-8}{7}$
• D. $\frac{-16}{7}$

Answer 1

The correct option is C

$\frac{-8}{7}$

Cube root of $\frac{-512}{343}$ = $\sqrt[3]{3\frac{-512}{343}}$

= $\sqrt[3]{3\frac{-8\times -8\times -8}{7\times 7\times 7}}$

= $\frac{-8}{7}$