Question

Find the cube root of:
(i) 343
(ii) 1000
(iii) 2744
(iv) 74088 [4 MARKS]

Answer 1

Solution: 1 Mark each

$\left(i\right)343=7\times 7\times 7$

$\therefore \sqrt[3]{3343}=\sqrt[3]{37\times 7\times 7}$

$=7$


$\left(ii\right)1000=10\times 10\times 10$

$\therefore \sqrt[3]{31000}=\sqrt[3]{310\times 10\times 10}$

$=10$


$\left(iii\right)2744=2\times 2\times 2\times 7\times 7\times 7$

$\therefore \sqrt[3]{32744}=\sqrt[3]{32\times 2\times 2\times 7\times 7\times 7}$

$=2\times 7=14$


$\left(iv\right)74088=2\times 2\times 2\times 3\times 3\times 3\times 7\times 7\times 7$

$\therefore \sqrt[3]{374088}=\sqrt[3]{32\times 2\times 2\times 3\times 3\times 3\times 7\times 7\times 7}$

$=2\times 3\times 7=42$