Question

Find the cube root of the rational number.
$\frac{-686}{-2662}$

Answer 1

$$\begin{gathered} \sqrt[3]{\frac{-686}{-2662}} \\ =\sqrt[3]{\frac{686}{2662}} \\ =\sqrt[3]{\frac{343}{1331}} \\ =\sqrt[3]{\frac{7\times 7\times 7}{11\times 11\times 11}} \\ =\frac{7}{11} \end{gathered}$$